A cable is attached between BB and CC. The cable is attached in such a way that it has a tension of TBCTBC along its length. The tensile force will attempt to pull BB toward CC. The force exerted on BB has a z component with a magnitude of 10 lb10 lb . What is the magnitude of the tension in the cable, TBCTBC? Express your answer to three significant figures and include the appropriate units.

Ibelieve the correct answer would be c.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Ihope you find the answer