An inductor is hooked up to an AC voltage source. The voltage source has EMF V0 and frequency f. The current amplitude in the inductor is I0. Part A
What is the reactance XL of the inductor?
Express your answer in terms of V0 and I0.
Part B
What is the inductance L of the inductor?
Express your answer in terms of V0, f, and I0.

a. The reactance of the inductor is XL = V₀/I₀

b. The inductance of the inductor is L = V₀/2πfI₀

Explanation:

PART A

Since the voltage across the inductor V₀ = I₀XL where V₀ = e.m.f of voltage source, I₀ = current amplitude and XL = reactance of the inductor,

XL = V₀/I₀

So, the reactance of the inductor is XL = V₀/I₀

PART B

The inductance of the inductor is gotten from XL = 2πfL where f = frequency of voltage source and L = inductance of inductor

Since XL = V₀/I₀ = 2πfL

V₀/I₀ = 2πfL

L = V₀/2πfI₀

So the inductance of the inductor is L = V₀/2πfI₀

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explanation:

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