Tutoring Services: Suppose that 40% of community college students never use tutoring services available at their college. Suppose we randomly select samples of community college students. For each sample we calculate the proportion who do not use tutoring. If we randomly sample 500 students at a time, what will be the mean and standard error of the sampling distribution of sample proportions

The mean and standard error of the sampling distribution of sample proportions are 0.40 and 0.0219 respectively.

Step-by-step explanation:

Formula : Mean  of the sampling distribution of sample proportions

Standard error of the sampling distribution of sample proportions

, where p = population proportion

n= sample size

Here, p =0040

n= 500

So , Mean  of the sampling distribution of sample proportions

Standard error of the sampling distribution of sample proportions

Hence, mean and standard error of the sampling distribution of sample proportions are 0.40 and 0.0219 respectively.

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6

ok thats very interesting