David is driving at a steady speed (v) when he spots Tina 1000 m ahead of him. At that moment she accelerating at a steady rate (a) from rest, and moves towards him. At what instant will they reach the same position

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

The sunlight shines uv radiation on earth,a microwave oven radiates waves on food

The genes are more on the side of.. b nature