archer shoots his arrow towards a target at a distance of 90 m, and hits ‘bullseye’ . Calculate the acceleration and time taken by the arrow to hit the target with a velocity of 90.0 m/s

a =45 m/s2

t = 2 seconds

Explanation:

Hi, to answer this question we have to apply the next formula:

v^2 = u^2 +2 a d

Where:

v = final velocity = 90 m/s

u = initial velocity = 0 m/s (shots from rest)

a = acceleration (m/s2)

d = distance = 90m

90^2 = 0^2 + 2a(90)

Solving for a:

8,100= 180 a

8,100/180 = a

a = 45 m/s^2

For time:

v = u + at

90 = 0 + 45t

90/45=t

t =2 seconds

d.7.5cm is your answer

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg