Astudent solved the equation sin2x/cos x = 2, 0 ≤ x ≤ pi, and got pi/2. what was the student's error?

sin(2x)/cos x = 2sin x*cos x/ cos x = 2 sin x = 2

sin x = 1

x = pi/2

but cos pi/2 = 0

so the given equation is indeterminate for x = pi/2

Answer with Step-by-step explanation:

We are given a equation:

Now, we will solve it

 2sinx=2

 sinx=1

all the possible values of x from 0 to π so that sinx=1 is

  x=π/2

but, cos(π/2) is indeterminate

need points to ask question

step-by-step explanation:

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3