Two point charges of charge Q = 15 nC and mass m = 33 g are 27 cm apart. One of them is let go. Gravity should be ignored.

What will its speed be when it has moved 16 cm?

Given that,

Charge = 16 nC

Mass = 33 g

Distance = 27 cm

We need to calculate the acceleration

Using formula of electrostatic force

Put the value into the formula

We need to calculate the speed of charge

Using equation of motion

Where, v= speed

u = initial speed

a = acceleration

s = distance

Hence, The speed of the charge is 0.0175 m

the answer would be c

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm