A box-shaped metal can has dimensions 6 in by 2 in by 12 in high. All of the air inside the can is removed with a vacuum pump. Assuming normal atmospheric pressure outside the can.

a. Find the total force on one of the 6 in by 12 in sides.
b. Find the gauge pressure at the bottom of a swimming pool that is 17 feet deep.

a) The total force is 4659.8 N

b) The gauge pressure is 50764 Pa

Explanation:

Given:

Pressure inside = 0

Patm = pressure outside = 1.013x10⁵Pa

Pressure difference = ΔP = 1.013x10⁵ - 0 = 1.013x10⁵Pa

a) The area is equal:

The force is:

b) The gauge pressure at the bottom is equal:

Where:

ρ = density = 1000 kg/m³

h = 17 ft = 5.18 m

Replacing:

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explanation:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.