A solenoid with 300 turns has a radius of 0.040 m and is 40 cm long. If this solenoid carries a current of 12 A, what is the magnitude of the magnetic field near the center of the solenoid? (μ 0 = 4π × 10-7 T · m/A)

The magnitude of the magnetic field near the center of the solenoid is 11.3 mT

Explanation:

No. of turns

Radius m

Length of solenoid m

Current A

For finding the magnetic field near the center of the solenoid is given by,

Where

    T

    mT

Therefore, the magnitude of the magnetic field near the center of the solenoid is 11.3 mT

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