A negative charge of - 2.0 C and a positive charge of 3.0 C are separated by 80 m. What is the force between the two charges?

-8.4 x 10^6N

Explanation:

Given that,

negative charge (q1) = -2.0C

positive charge (q2) = 3.0C

Distance between charges (r) = 80 m

force between the two charges (F) = ?

Apply the formula for

F= (kq1q2) / r^2

Recall that k is Coulomb's constant with a value of 9 × 10^9 Nm2C−2

Then,

F = (9 × 10^9 Nm2C−2 x -2.0C x 3.0C) / (80m)^2

F = (-5.4 x 10^10) / (6400m)^2

F = -8437500N

Place result in standard form

F = -8.4 x 10^6N

Thus, the force between the two charges is -8.4 x 10^6 newton

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards