The power supplies in 1206 Mudd feature an internal protection mechanism that limits the output current to 1 ampere. ldeally, the protection circuit engages instantaneously when an over-current fault is detected, then disengages instantaneously once the fault condition is removed. While in the current limited state, the supply acts like an ideal current source. Now suppose you set a supply to 5V then connect a fully discharged ideal 500mF (huge!) capacitor to the the output. The supply will immediately go into current-limit (a) why?(b) approximately how long would it take the power supply to come out of current limit?(c) plot the voltage across the capacitor from the time it is connected to the supply until the time calculated in (b) disengages? into current limit, but it would stay that way until the wire was removed. What (d) what current would be drawn from the supply several seconds after the protection(e) a wire (short circuit) placed across the power supply output also would cause it to go value of capacitor would have the same effect?