A 1.2-m3 rigid tank contains nitrogen gas at 200 kPa and 350 K. Now heat is transferred to the nitrogen in the tank and the pressure of nitrogen rises to 900 kPa. The work done during this process is

Work done is 0 J.

Explanation:

Given:

Volume of the tank (V) = 1.2 m³

Initial pressure of nitrogen (P₁) = 200 kPa

Initial temperature of nitrogen (T₁) = 350 K

Final pressure of nitrogen (P₂) = 900 kPa

The volume of nitrogen gas is same as volume of tank. Now, as the tank is rigid, the volume of nitrogen gas remains the same.

We know that,

Work done on a gas is given as:

Where, ΔV is the change in volume.

But, the volume here is constant. So, ΔV = 0.

Hence, the work done is also zero.

unbalanced force

explanation:

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards