If a constant friction force of magnitude 11 Newtons is exerted on the block by the surface, find the magnitude of the acceleration of the block. Answer in units of m/s 2

acceleration a = 3.67 m/s^2

Completed Question:

A block of mass 3 kg, which has an initialspeed of 6 m/s at timet= 0, slides on ahorizontal surface. If a constant friction force of magnitude 11 Newtons is exerted on the block by the surface, find the magnitude of the acceleration of the block. Answer in units of m/s 2

Explanation:

Force = mass × acceleration

F = ma 1

Given that;

Force F = 11 N

mass m = 3 kg

Acceleration a can be derived from equation 1

Making a the subject of formula;

a = F/m

Substituting the given values;

a = 11N/3kg

a = 3.66666... m/s^2

acceleration a = 3.67 m/s^2

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

f is prop to m1xm2 double m1 double force