According to Equation 20.7, an ac voltage V is given as a function of time t by V = Vo sin 2ft, where Vo is the peak voltage and f is the frequency (in hertz). For a frequency of 48.3 Hz, what is the smallest value of the time at which the voltage equals one-half of the peak-value?

Explanation:

Given:

The equation for voltage (V) in terms of frequency (f) and time (t) is given as:

Where, is the peak voltage.

Frequency (f) = 48.3 Hz

Voltage (V) = Half of peak voltage =

Now, plug in the given values in the above equation and solve for 't'. This gives,

Therefore, the smallest value of the time at which the voltage equals one-half of the peak-value is