A metal sphere with radius R1 has a charge Q1. Take the electric potential to be zero at an infinite distance from the sphere. Express your answer in terms of the given quantities and appropriate constants.1. What is the electric field at the surface of the sphere?E=2.What is the electric potential at the surface of the sphere?V=

(a) E = KQ1/R₁²

(b) V = KQ1/R1

Explanation:

Given -

Radius of the sphere = R1

Charge of the sphere = Q1

(a)

Electric field created by a point charge can be expressed as

E = q/4π∈₀r² =  Kq/r²

Where, ∈₀ is the permittivity of free space

             r is the distance between the charge and the point

             K = 1/4π∈₀ = 9 X 10⁹ Nm²/C² (Coulomb's constant )

Therefore, the electric field at the surface of the sphere is:

E = KQ1/R₁²

(b)

The electric potential due to a point charge at a point is given by

V = q/ 4π∈₀r = Kq/r

Therefore, the electric potential at the surface of the sphere is

V = KQ1/R1

i wanna say it’s between b and d, leaning more towards b.