How many joules are released as 10.0g of steam at 110℃ cools to produce water at 25℃?

26,000 J

Explanation:

Heat released when the steam is cooled:

q = mCΔT

q = (10.0 g) (2.02 J/g/K) (100℃ − 110℃)

q = -202 J

Heat released during condensation (gas to liquid):

q = mL

q = (10.0 g) (-2260 J/g)

q = -22,600 J

Heat released when the liquid water is cooled:

q = mCΔT

q = (10.0 g) (4.184 J/g/K) (25℃ − 100℃)

q = -3138 J

Total heat released:

q = -202 J − 22,600 J − 3138 J

q = 25,940 J

Rounded to two significant figures, 26,000 J of heat are released.

explanation:

a fuel engine ( known as a gasoline engine in american english )is an internal combustion engine with spark ignition, designed to run on petrol (gasoline) and similar volatile fuels.

i dont think you are wrong for wanting to get even with someone who did you wrong.

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