How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 4.00 cm2?

Explanation:

Let us assume that the separation of plate be equal to d and the area of plates is . As the capacitance of capacitor is given as follows.

            C =

It is known that the dielectric strength of air is as follows.

               E =

Expression for maximum potential difference is that the capacitor can with stand is as follows.

                       dV = E × d

And, maximum charge that can be placed on the capacitor is as follows.

               Q = CV

                   =

                   =

                   =

                   =

or,                = 10.62 nC

Thus, we can conclude that charge on capacitor is 10.62 nC.

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.

wavelength divides in half and speed stays the same.