An electron is released from rest at a perpendicular distance of 9.3 cm from a line of charge on a very long nonconducting rod. That charge is uniformly distributed, with 6.7 μC/m. What is the magnitude of the electron's initial acceleration?

Explanation:

The electron is negatively charged .The magnitude of force acting on on electron is

F=|e| E

Where E is electric field of long non conducting rod E=1/2πε₀r with linear charge density λ=6.7μC/m

From Newtons second laws

the initial acceleration of electron is given by:

a=(|e|λ) /2πε₀rm= 2(|e|λ) / 4πε₀rm

Where 2 is multiplied on both numerator and denominator   to simplify calculation

The electron is initially at distance r=9.3cm=0.093 m from rod

So

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gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.