A proton (rest mass 1.67×10−27kg) is moving at 0.905 c. Find the momentum of the proton. Express your answer with the appropriate units.

  P= 4.52 x 10⁻¹⁹  kg.m/s

Explanation:

Given that

m = 1.67 x 10⁻²⁷ kg

V= 0.905 C

We know that

C= 3 x 10 ⁸ m/s

Therefore ,V= 0.905 x  3 x 10 ⁸ m/s

V= 2.71 x 10 ⁸ m/s

The linear momentum P is given as

P= m V

P= 1.67 x 10⁻²⁷ x 2.71 x 10 ⁸  kg.m/s

P= 4.52 x 10⁻¹⁹  kg.m/s

Therefore the answer will be  4.52 x 10⁻¹⁹  kg.m/s.

c.is a substance that requires a small amount of energy per gram to raise its temperature; has strong cohesive forces between molecules.

explanation:

a colorless, transparent, odorless liquid that forms the seas, lakes, rivers, and rain and is the basis of the fluids of living organisms.