What would the radius (in mm) of the Earth have to be in order for the escape speed of the Earth to equal the speed of light (3 x 108 m/s)? You may ignore all other gravitational interactions for the rocket and assume that the Earth-rocket system is isolated.

Radius in mm will be 4.425 mm        

Explanation:

We have given given escape speed of earth is equal to speed of the light as

Gravitational constant

Mass of the earth

We have to find the radius of the earth

We know that escape speed is

So

Squaring both side

So radius in mm will be 4.425 mm

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.