A proton is fired from far away toward the nucleus of a mercuryatom. Mercury is element number 80, and the diameter of the nucleusis 14.0 fm. If the proton is fired at a speed of 4.0 \times 10^{7}\;{\rm m}/{\rm s},what is its closest approach to the surface of the nucleus?

a) Assume the nucleus remains at rest.
The unit is (fm)

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

e/c, where e is its total energy

multiple allele inheritance is traits controlled by more than 2 alleles (ex: pigeons having 3 alleles of one gene govern their feather color).