A pipe that is 0.92 m long and open at both ends vibrates in the second overtone with a frequency of 584 Hz. What is the speed of sound in the air in this pipe

362.08 m/s.

Explanation:

The formula for the second over tune of an open pipe is

F = 3v/2l Equation 1

Where F = frequency of the third over tone, v = velocity of sound in air, l = length of the pipe.

Make v the subject of the equation,

v = 2Fl/3 Equation 2

Given: F = 584 Hz, l = 0.93 m,

Substitute into equation 2

v = 2×584(0.93)/3

v =  362.08 m/s.

Hence the speed of sound in air = 362.08 m/s.