Water drips from the nozzle of a shower onto the floor 189 cm below. the drops fall at regular (equal) intervals of time, the first drop striking the floor at the instant the fourth drop begins to fall. when the first drop strikes the floor, how far below the nozzle are the (a) second and (b) third drops?

0.83999 m

0.20999 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s² = a

s = 189 cm

When the time intervals are equal, if four drops are falling then we have 3 time intervals.

So, the time interval is

For second drop time is given by

Distance from second drop

Distance from second drop is 0.83999 m

Distance from third drop

Distance from third drop is 0.20999 m

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

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