Asealed tank containing seawater to a height of 10.7 m also contains air above the water at a gauge pressure of 3.20 atm. water flows out from the bottom through a small hole. how fast is this water moving?

28.97 m/s

Explanation:

height of water (H1) = 10.7 m

Gauge pressure (Pg) = 3.2 x 1.01325 x 10^{5} = 324240 N/ m^[2}

pressure at the top (P1) = gauge pressure (Pg) + atmospheric pressure(Pa)  (Pg + Pa)

acceleration due to gravity (g) = 9.8 m/s^{2}

height at the bottom (H2) = 0

pressure at the bottom (P2) = atmospheric pressure = (Pa)

density of sea water (ρ) = 1030 kg/m^{3}

speed of water at the top (V1) = 0 (assuming the tank is big, the speed of water at any point on the surface is almost 0 and also the hole is very small compares to the size of the tank)

speed of water at the top (V2) = ?

applying Bernoulli's equation we can find the value of V2.

(take note that represents ρ whcih is the density of sea water)

recall that P1 = Pg + Pa and P2 = Pa

)

)

V2 =

V2 =

V2 = 28.97 m/s

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.