To assess whether your calculations make sense, let's simplify the problem even further and assume air resistance is negligible. in this case, the net force acting on the bicyclist is equivalent to just the force of static friction, and your answer to part d is the magnitude fs. based on this value, what is the minimum coefficient of static friction μs between the race track and the bicycle? express your answer numerically to two significant figures. v
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Physics, 21.06.2019 13:30
Acar is traveling at 53.0 mi/h on a horizontal highway. (a) if the coefficient of static friction between road and tires on a rainy day is 0.104, what is the minimum distance in which the car will stop?
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Physics, 22.06.2019 09:30
Asap i'm in class rn a 1,000-kg car is traveling 20 m/s on a flat stretch of road. it gets to a hill and coasts uphill until it stops. how high up the hill does the car travel? givens: equation: 1/2mv2initial=mghfinal solve for h. plug & chug, label.
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Physics, 23.06.2019 00:30
Why is no-till farming more sustainable than many traditional methods of farming
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Physics, 23.06.2019 01:00
Learning goal: to understand newton's 1st law. newton's principia states this first law of motion: an object subject to no net force maintains its state of motion, either at rest or at constant speed in a right line. this law may be restated as follows: if the sum of all forces acting on an object is zero, then the acceleration of that object is zero. mathematically this is just a special case of the 2nd law of motion, f⃗ =ma⃗ , when f⃗ =0. when studying newtonian mechanics, it is best to remember the 1st law in two ways: if the net force (i.e., sum of all forces) acting on an object is zero, the object will keep moving with constant velocity (which may be zero). if an object is moving with constant velocity, that is, with zero acceleration, then the net force acting on that object must be zero. complete the following sentences to see if you can apply these ideas. part a if a car is moving to the left with constant velocity, one can conclude that
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To assess whether your calculations make sense, let's simplify the problem even further and assume a...
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