A19 kg solid disk of radius0.44 m is rotated about an
axisthrough its center. if the disk accelerates from rest to an
angularspeed of 2.5 rad/s while rotating1.0 revolutions, what net
torque isrequired?

0.915 Nm

Explanation:

1 revolution = 2π rad

We can use the following equation of motion to find out the acceleration acting on the disk

where = 0 rad/s is the initial velocity of the can when it starts from rest, is the angular distance traveled, is the angular acceleration of the disk, which we care looking for:

The moment of inertia of the solid disk is:

where m is the mass and R is the radius of the disk

The net torque applied is

t.                 w               e                 n                   t                 y                 c             h               a           r           a               c                 t             e             r             s        

ι вєℓιєνє ιт ιѕ тнє fιяѕт ¢нσι¢є(α.)

нє ѕнσυℓ∂ ѕмιℓє ρσℓιтℓу αи∂ ѕρєαк тσ тнє ρєяѕσи ωнσ ιѕ ιитєяяυριиg αfтєя тнє ∂ιѕ¢υѕѕισи

нσρє ι ¢συℓ∂ нєℓρ.