ON A TIMER Consider the reaction below. *Image* Which is the net ionic equation for the reaction?

C2H3O2^-(aq) + H^+ —> HC2H3O2

Explanation:

The following equation was given in the question:

Na^+ + C2H3O2^-(aq) + H^+ Cl^- —> Na^+ + Cl^- + HC2H3O2

Now, to obtain the net ionic equation, we simply cancel out the ions common to both side of the equation.

A careful observation of the equation above, shows that sodium ion, Na^+ and chloride ion, Cl^- are common to both side of the equation.

Therefore, to obtain the net ionic equation, we simply cancel out Na^+ and Cl^- from both side of the equation. This is illustrated below:

Na^+ + C2H3O2^-(aq) + H^+ Cl^- —> Na^+ + Cl^- + HC2H3O2

C2H3O2^-(aq) + H^+ —> HC2H3O2

Therefore, the net ionic equation is

C2H3O2^-(aq) + H^+ —> HC2H3O2

wher is the rest of the question

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.