Physics, 08.01.2020 22:31 gracedaniels68

Anon-licensed person may be the sole owner of a civil, electrical, or mechanical engineering business under which of the following conditions

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Answer from: probablyacommunist

hi your question lacks the options here is the complete question

A non-licensed person may be the SOLE owner of a civil, electrical, or mechanical engineering business under which of the following conditions

(a) A currently licensed California Civil, Electrical, or Mechanical Engineer, as appropriate, is in charge of the engineering practice of the business.

(b) All engineering plans and specifications are prepared by an appropriately licensed engineer.

(d) None. No provisions exist.

Explanation:

Generally a non-licensed person is not allowed to be a sole owner of an engineering business because it requires engineering plans and specifications to be made and carried out hence a certified/licensed Engineer alone can do that.

from the conditions given the only condition suitable for a non-licensed person to be the sole owner of an engineering business is that the engineering plans and specifications are prepared by an appropriately licensed engineer either working for the engineering business or contracted .

Answer from: Quest

protons in

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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