Awire connected to a 9 v battery records a current of 3.6 a in an ammeter. what is the resistance of the wire?

R=2.5 ohm

Explanation:

Given that   :

Voltage difference = 9 V

Current ,I= 3.6 A

As we know that from Ohm's law

V= I R

V =Voltage difference

I=Current

R=Resistance of the wire

Now by putting the values in the above equation we get

9 = 3.6 R

R=2.5 ohm

Therefore the resistance of the wire will be 2.5 ohm.

the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas