What is the reynolds number for blood leaving the heart through the aorta if the diameter of the aorta is 2.15 cm and the blood has a dynamic viscosity of 2.70 × 10-3 pa·s, a density of 1050 kg/m3, and travels at a mean fluid velocity of 28.9 cm/s?

Reynolds number will be 2416.3611

Explanation:

We have given diameter of aorta d = 2.15 cm = 0.0215m

Dynamic viscosity of blood

Fluid velocity

Fluid density

We have to find the Reynolds number

We know that  Reynolds number is given by

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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think its the third option