1. an airow is shot horizontally from a crossbow 1.5 m above the ground. the initial velocity is 45
m/s. how long will the arrow travel through the air before hitting the ground?

Time taken by the arrow to travel along to hit the ground is 0.55 seconds.

Explanation:

The only "force" acting on the "crossbow" to cause it to "hit" the ground is "gravity". There is no initial velocity downward when it shoot.

d = the displacement of the object  

t = the time for which the object moved  

a = acceleration of the object  

= the initial velocity of the object

Given values

d = 1.5 m

t = unknown

Square root both sides

t = 0.55 s

the answer is b

explanation:

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.