An aluminum electric tea kettle with a mass of 500 g is heated with a 500-w heating coil. how long will it take to heat up 1.0 kg of water from 18°c to 98°c in the tea kettle

669.76s or 11.16mins

Explanation:

Mass of kettle (Mk) = 500g

Mass of water (Mw) = 1.0kg = 1000g

Power = 500w

θ₁ = 18°C

θ₂ = 98°C

specific heat capacity of water (c) = 4.186J/g*°C

Q (work done) = ?

Q = MC∇θ

Q = Mc (θ₂ - θ₁)

The work done in raising 1kg of water from 18°c to 98°c = Q

Q = 1000 * 4.186 * (98 - 18)

Q = 1000 * 4.186 * 80

Q = 334880J

But power = workdone / time

Time = workdone / power

Time = Q / P

Time = 334880 / 500

Time = 669.76s

T = 11.16mins

The time taken to heat 1kg of water from 18°C to 98°C is 669.76s

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement