The perimeter of a rectangle is 44 ft. the length is 6 ft longer than the width. find the dimensions. write a system of linear equations and solve the resulting system. let x be the length and y be the width.

X= length= y+6
y= width
P= perimeter

P= 2x + 2y
44= 2(y+6) + 2y
44= 2y + 12 + 2y
44= 4y + 12
subtract 12 from both sides
32= 4y
divide both sides by 4
8 ft= y

Substitute y=8 to find x
44= 2x + 2y
44= 2x + 2(8)
44= 2x + 16
subtract 16 from both sides
28= 2x
divide both sides by 2
14 ft= x

ANSWER: Length is 14 feet and width is 8 feet.

Hope this helps! :)

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