Physics, 07.12.2019 01:31 hjfcjds

Question 17 a sample of iron is put into a calorimeter (see sketch at right) that contains of water. the iron sample starts off at and the temperature of the water starts off at . when the temperature of the water stops changing it's . the pressure remains constant at . calculate the specific heat capacity of iron according to this experiment. be sure your answer is rounded to the correct number of significant digits.

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Answer from: jexvilla

Complete Question:

A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.

Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits

(Question attached)

$c_{iron}=0.568 J/kg.\°C$

$c_{iron}=0.6 J/kg.\°C$ (rounded to 1 decimal place)

Explanation:

A calorimeter is used to measure the heat of chemical or physical reactions. The example given in the question is using the calorimeter to determine the specific heat capacity of iron.

When the system reaches equilibrium the iron and water will be the same temperature, $T_{e}$ . The energy lost from the iron will be equal to the energy gained by the water. It is assumed that the only heat exchange is between the iron and water and no exchange with the surroundings.

$Q=mc(T_{e}-T_{initial})$ (Eq 1)

$-Q_{iron}=Q_{water}$ (Eq 2)

Water:

$m_{water}=100.0 g, c_{water}=4.186 J/kg.\°C, T_{initial,water}=23 \°C, T_{e}=27.6 \°C$

Iron:

$m_{iron}=59.1 g, c_{iron} = ? J/kg.\°C, T_{initial,iron}=85 \°C, T_{e}=27.6 \°C$

Substituting Eq 1 into Eq 2 and details extracted from the question:

$-m_{iron}c_{iron}(T_{iron,e}-T_{initial})=m_{water}c_{water}(T_{water,e}-T_{initial})$

$-59.1*c_{iron}(27.6-85)=100.0*4.186(27.6-23)$

$c_{iron}=0.568 J/kg.\°C$

$c_{iron}=0.6 J/kg.\°C$

Question 17 a sample of iron is put into a calorimeter (see sketch at right) that contains of water.

Answer from: Quest

it is very well related to a lot of things but with my limited knowledge i can confidently say that the answer is space.

Answer from: Quest

An atom (ours, not carroll's) consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons. the positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral. most of an atom's mass is in its nucleus; the mass of an electron is only 1/1836 the mass of the lightest nucleus, that of hydrogen. although the nucleus is heavy, it is quite small compared with the overall size of an atom. the radius of a typical atom is around 0.1 to 0.25 nanometres (nm), whereas the radius of a nucleus is about 10-6 nm. * if an atom were enlarged to the size of the earth, its nucleus would be only 200 feet in diameter and could easily rest inside a small football stadium.read more on -

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Question 17 a sample of iron is put into a calorimeter (see sketch at right) that contains of water....

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