.What is the crude mortality rate for Regionville? Regionville is a community of 100,000 persons. During 1985 there were 1,000 deaths from all causes. All cases of tuberculosis have been found and they total 300 – 200 males and 100 females. During 1985, there were 60 deaths from tuberculosis, 50 of the males.

A. 300 per 100,000
B. 60 per 1,000
C. 10 per 1,000
D. 100 per 1,000
E. 200 per 1,000

C

Step-by-step explanation:

Crude mortality rate= total no of deaths in 1 year ÷ total population per 1000

total number of death that year 1985 is 1000 and the total population is 100000

= 1000/100,000

= 10 per 1000.

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: