Particles of charge q and 3q are placed on the x-axis at x=-40 and x=50, respectively. a third particle of charge q is placed on the x-axis, and the total electric force on this particle is zero. determine the position of the particle.

x = -7.06 cm

Explanation:

The distance of new charge q from origin = x

We know that force between two charge given as

Given that the force on the third charge q is zero.

Therefore

3(40+x)² = (50-x)²

50 - x = 69.28  + 1.73 x

2.73 x = 50 - 69. 28

x = -7.06 cm

Therefore the third charge on the negative x axis and distance from origin will be 7.06 cm.

area of focus