Comets travel around the sun in elliptical orbits with large eccentricities. if a comet has speed 1.6×104 m/s when at a distance of 2.7×1011 m from the center of the sun, what is its speed when at a distance of 4.8×1010 m?

v₂ = 7.6 x 10⁴ m/s

Explanation:

given,

speed of comet(v₁) = 1.6 x 10⁴ m/s

distance (d₁)= 2.7 x 10¹¹ m

to find the speed when he is at distance of(d₂) 4.8 × 10¹⁰ m

v₂ = ?

speed of planet can be determine using conservation of energy

K.E₁ + P.E₁ = K.E₂ + P.E₂

v₂ = 7.6 x 10⁴ m/s

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

trig 15.3 cos