Calculate what volume of the following solutions is required to obtain 0.261 mol of each solute
(a) 0.281 M AICI:
(b) 2.19 M HCI

a) V sln = 0.9288 L

b) V sln = 0.1192 L

Explanation:

∴ mol solute = 0.261 mol

a) C AlCl = 0.281 M

⇒ V sln = (0.261 mol)*(L sln/0.281 mol)

⇒ V sln = 0.9288 L

b) C HCl = 2.19 M

⇒ V sln = (0.261 mol)*(L/2.19 mol)

⇒ V sln = 0.1192 L

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