Achild of mass 49.7 kg sits on the edge of a merry-go-round with radius 2.7 m and moment of inertia 311.589 kg m2 . the merrygo-round rotates with an angular velocity of 2.8 rad/s. what radial force does the child have to exert to stay on the merry-go-round? answer in units of n.

The radial force is F_c = 1052.04 N

Explanation:

Given to find the radial force

m = 49.7 kg

r1 = 2.7 m

I = 311.589 kg*m^2

ω = 2.8 rad/s

F_c = m*r1 *ω²

To find the angular force to stay on the merry go round

so replacing numeric:

F_c = 49.7 kg* 2.7m* (2.8 rad/s ^2)  

F_c = 1052.04 N

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.