Awagon having a mass of 91 kg is accelerated across a peel road of 0.97. what net force act on the wagon horizontally

The net force on the wagon will be 88.27N

Explanation:

Mass of Wagon = m = 91kg  

Acceleration of wagon = a = 0.97kgm/s^2  

Net force on wagon = F = ?

According to Newton’s second law of motion:

“When a force is applied on a body, acceleration is produced in it in the direction of force”. Mathematically, it can be represented as:  

                                            F = ma      ……… (i)

By putting values in equation (i),  

                                           F = (91)(0.97)

                                           F = 88.27N