Ashopper pushes a 7.32 kg grocery cart
with a 14.7 n force directed at
-32.7° below the horizontal.
what is the normal force on the cart?

The "normal force" on the "cart" 63.893 N .

Explanation:

To find normal force on the cart, use the equation

Normal force  = mg + F sinx,  

“m” being the object's mass,  

“g” being the acceleration of gravity,

“x” being the angle of the cart

Given values

M = 7.33 kg

F = 14.7 N

Substitute the values in above equation

Normal force = (7.33 × 9.8) + 14.7 sin(-32.7°)

Normal force = 71.834 + 14.7 × (-0.5402)

Normal force = 71.834 - 7.94094

Normal force = 63.893 N

The "normal force" on "the cart" 63.893 N .

1 a

2 b

3 b

4 d

5 d

6 d

explanation:

probably not if net force is zero