Asatellite is in a circular orbit around the earth at an altitude of 3.76 106 m.(a) find the period of the orbit. (hint: modify kepler's third law: t2 =4p2gmsr3so it is suitable for objects orbiting the earth rather than the sun. the radius of the earth is 6.38 106 m, and the mass of the earth is 5.98 1024 kg.)1 h(b) find the speed of the satellite.2 km/s(c) find the acceleration of the satellite.3 m/s2 toward the center of the earth

To solve the problem we need to know the Satellite Period, given by,

It is also necessary to identify the satellite speed, which is given,

Finally, it is required to know the satellite acceleration, given by,

By definition, the radius of the earth is 6.371 * 10 ^ 6m measured from the center of the earth and that the mass is and that the gravitational constant is

On the other hand, the distance from the earth's surface to the satellite point of

Then the net distance, from the center of the earth to the point of the Satellite would be given by,

With the previous values obtained it is possible to obtain the period, as well,

In turn with the previously found data and using the velocity formula we can calculate it,

Once the speed is obtained we can proceed to calculate the acceleration, for this we apply in the acceleration equation,

So we have,

Part a= 2h45m

Par b =

Part c=

pe = weightxheight = 2000x1000=2,000,000joules

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