What is the sum of the infinite geometric series?

The answer is going to be D -6

r=1/2

Sn=a(1-r^n)/1-r

S(infinite sign) = a/1-r

S(infinite sign) = -3/1-1/2

S(infinite sign) = -3/1/2

S(infinite sign) = -3/1/1*2/2-1/2

S(infinite sign) = -3/1*2/2-1/2

S(infinite sign) = -3(3*2)

S(infinite sign) = -1*6

S(infinite sign) = -6

0/5 is 0, 2/0 is undefined, and 0/0 is indeterminate.

step-by-step explanation:

hope my answer has you!