Apuck of mass m = 0.085 kg is moving in a circle on a horizontal frictionless surface. it is held in its path by a massless string of length l = 0.72 m. the puck makes one revolution every t = 0.45 s. part (a) what the magnitude of the tension in the string, in newtons, while the puck revolves?

The magnitude of the tension of the in string is 12.04 N.

The given parameters;

mass of the puck, m = 0.085 kg

length of the string, L = 0.72 m

time for a complete revolution, t = 0.45 s

The magnitude of the tension of the in string is determined by calculating the centripetal force on the circular motion;

where;

v is the linear velocity (m/s)

r is the radius of the path (m)

The angular speed is calculated as;

The linear velocity is calculated as;

v = ωr

v = 13.96 x 0.72

v = 10.1  m/s

The magnitude of the tension of the in string;

Thus, the magnitude of the tension of the in string is 12.04 N.

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explanation:

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.