9. What is the total kinetic energy (KEtran + KErot) of a solid cylinder with mass M = 2.50 kg and radius R = 0.5 m that rolls without slipping down a 4.50 m high hill, starting from rest? (Here we assume that there is no energy loss due to friction. I = 1 2 MR2 ,ω = v / R )

110.25 J

Explanation:

We are given that

Mass,M=2.5 kg

Radius,R=0.5 m

Distance,d=4.5 m

Initial speed,u=0

We have to find the total kinetic energy

According to law of conservation of energy

Total kinetic energy=Potential energy=mgh

Where g=

Using the formula

Total kinetic energy=

Total kinetic energy

32: from largest to smallest, this hierarchy includes eons, eras, periods, epochs, and ages.

33: answer is c

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