Acar traveling at 30 m/s drives off a cliff that is 50 meters high? how far away does it land?

The maximum range m

Explanation:

Given,

The initial velocity of the car, u = 30 m/s

The height of the cliff, h = 50 m

Let the car drives off the cliff with a horizontal velocity of 30 m/s.

The formula for a projectile that is projected from a height h from the ground is given by the relation

                                 m

Where,

                          g - acceleration due to gravity

Substituting the values in the above equation

                                          = 132.72  m

Hence, the car lands at a distance, m            

for this one it would be d bump/forearm pass

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.