What is the momentum of a 5 kg object that has a velocity of 1.2 m/s ?

3.8 kg • m/s
4.2 kg • m/s
6.0 kg • m/s
6.2 kg • m/s

The momentum, p = 6 kg • m/s

Explanation:

Given that,

Mass of the object, m = 5 Kg

Velocity of the object, v  = 1.2 m/s

The momentum of the body is defined as the product of the mass and velocity of the body. It is denoted by the letter 'p'

                                      p = mv

Substituting the values in the above equation

                                      p = 5 Kg x 1.2 m/s

                                         = 6 kg • m/s

Hence, the momentum of the object is p = 6 kg • m/s

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y