HELP PLS I NEED THIS LUV U

24

Step-by-step explanation:

the set of numbers are{3,2,7,9}  four numbers

you have 4 choices n!=4!=4*3*2*1=24

the number of choices minus set of 3 digit numbers(no repetition)

(n-r)! without repetition :(4-3)!=1!=1

P=24 3-digit numbers if no repetition allowed

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.