Arace car is traveling at 76 m/s when it slows down at 9 m/s^2 for 4 seconds. what is his new velocity

40m/s

Explanation:

Parameters.

Speed = 76m/s

Acceleration = 9m/s2

Time = 4seconds

We know that velocity (V1) = V2 + at

Where V1 is the final velocity, V2 is Initial velocity, a is acceleration but in this case it’s decceleration meaning the value will be negative and t is the time taken.

Therefore, V1 = V2 + a t

V1 = 76m/s + (-9m/s2) (4s)

V1 = 40m/s

Therefore the new final velocity is 40m/s

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