Physics, 21.10.2019 23:30 jessicannoh5965

A0.450-kg ice puck, moving east with a speed of 5.60m/s , has a head-on collision with a 0.950-kg puck initially at rest. assume that the collision is perfectly elastic. (1)- what is the speed of the 0.450-kg puck after the collision? (2)- what is the direction of the velocity of the 0.450- puck after the collision? (i)- to the east (ii)- to the west (3)- what is the speed of the 0.950-kg puck after the collision? (4)- what is the direction of the velocity of the 0.950-kg puck after the collision? (i)-to the east (ii)- to the west

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Answer from: neariah24

1) The disc speed of 0.450 kg is vif = -2.0 m / s

2) The disc is receding because the negative bone velocity is heading west

3) Disc speed 0.950 kg V2f = 3.6 m / s

4) The disk follows the initial direction of the light disk, bone moves east

Explanation:

For the problems of crashes we have to define a system in this case the system is formed by the two disks, write the amount of movement before and after the crash

p₀ = m₁ v₁₀ + 0

pf = m₁ v₁f + m₂ v₂f

For the system during the crash all forces are internal, so the moment is preserved

po = pf

m₁ v₁₀ = m₁ v₁f + m₂ v₂f

Like elastic shock, kinetic energy is also conserved

Ko = Kf

½ m₁ v₁₀² = ½ m₁ v₁f² + ½ m₂ v₂f²

Let's write the system of equations

m₁ (v₁₀ -v₁f) = m₂ v₂f

m₁ (v₁₀² - v₁f²) = m₂ v₂f²

We replace the first in the second

m₁ (v₁₀² - v₁f²) = m₂ [m₁ (v₁₀ -v₁f) / m₂]²

m₁ (v₁₀² - v₁f²) = [m1² (v₁₀ -v₁f)² / m₂

(v₁₀² - v₁f²) = [m₁ (v₁₀ -v₁f)² / m₂

m₁ (v₁₀ - v₁f) (v₁₀ + v₁f) = [(v₁₀ -v₁f)² m₁ / m₂

(v₁₀ + v₁f) = (v₁₀ -v₁f) m₁ / m₂

v₁f (1+ m₁ / m₂) = v₁₀ (m₁ / m₂ -1)

v₁f (m₂ + m₁) / m₂ = v₁₀ (m₁ -m₂) / m₂

v₁f = v₁₀ [(m₁ -m₂) / (m₁ +m₂)]

We calculate

V₁f = 5.6 [(0.450 -0.950) / ((0.450+ 0.90)] = 5.6 (-0.500 /1.4)

V₁f = - 2.0 m / s

The negative sign indicates that the disk goes back

m₁ (v₁₀ -v₁f) = m₂ v₂f

v₂f = m₁ / m₂ (v₁₀ -v₁f)

v₂f = 0.450 / 0.950 (5.6 - (-2))

v₂f = 3.6 m / s

Let's write the results

1) The disc speed of 0.450 kg is vif = -2.0 m / s

2) The disc is receding because the negative bone velocity is heading west

3) Disc speed 0.950 kg V2f = 3.6 m / s

4) The disk follows the initial direction of the light disk, bone moves east

Answer from: Quest

answer: what are you talking about?

explanation:

Answer from: Quest

Answer: it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.explanation: we have equation of motion $s=ut+\frac{1}{2} at^2$ ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/s $s=0*t+\frac{1}{2} *2.18*t^2$ $s=1.09t^2[/ 2equating equation 1 and 2 [tex]4.75t = 1.09t^2\\ \\ t=4.36 seconds.$ so it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.

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A0.450-kg ice puck, moving east with a speed of 5.60m/s , has a head-on collision with a 0.950-kg pu...

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